Question

a chemist has two solutions of hydrochloric acid in stock one is 50% solution and the other is 80% solution how much of each should be used to obtain hundred ml of 68% solution ​

Answer 1

Answer:

let x ml taken from 50% solution and y ml taken from 80 % solution.

'y'ml = (100 - x) ml [since total sol is 100 ml]

now 50 % of x + 80% of (100 - x) = 68 % of 100

1/2 x + 4/5 × 100 - 4/5× x = 68/100 × 100

0.5 x + 80 - 0.8x = 68

-0.3 x = 68- 80= -12

x = 12/ 0.3

x = 60 ml.

then y = 40 ml.

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