Question

A chemist has two solutions of hydrochloric acid in stock. One is 50% solution and the other is 80% solution. How much of each should be used to obtain 100ml of a 68% solution. by elimination method or substitution method​

Answer 1

Answer:

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Answer 2

Answer:

Let x ml taken from (100 - x) ml [since ml] now 50 % of x+ (100 - x) = 68 % 100 1/2 x + 4/5 x 100 - 4/5x x = 68/100 100 0.5 x + 80 - 0.8x = 68 -0.3 x = 68- 80= -12 x = 12/ 0.3 x = 60 ml. then y = 40 ml.

Step-by-step explanation:

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