A chemist mixed an acid of 48% concentration with the same acid of 80% concentration and then added 2 litres of distilled water to the mixed acid as a result he got 10 litres of the acid of 40% concentration how many milliliters of the acid of 48% concentration had the chemist used?
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Answer:
7500 ml
Step-by-step explanation:
Total mixture chemist got = 10 litre
Concentration = 40%
Acid = (48/100) * 10L = 4L
2 litres of distilled water was added to get final mixture
Hence two acid mixed were = 8 Litre
Let say X litre of 48% Concentration was added
then 8-x litre of 80% concentration was added
=> Acid = (48/100)x + (80/100)(8 - x)
(48/100)x + (80/100)(8 - x) = 4
=> 48x + 640 - 80x = 400
=> 240 = 32x
=> x = 7.5
7.5 litre = 7500 ml
7500 ml acid of 48% concentration the chemist used
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