Question

A chemist places a 100 g cube of each of the metals listed in the table on a separate hot plate. All of the hot plates are identical. Each hot plate is set on medium heat, and all of the cubes have the same initial temperature. Based on the specific heat values in the table, rank the metals in terms of how quickly they will reach the target temperature of 80°C. Use "1" to indicate the fastest and "5" to indicate the slowest.

Answer 1

Answer:

This is the answer

Explanation:

Answer 2

Therefore the increasing order of time taken is given by Pb < Sn < Cu < Fe < Al.

Given:

Mass of each cube = 100 g

Initial Temperature of all cubes = Tₐ

Final Temperature of all cubes = 80 °C

Specific heat of Iron( Fe ) = 0.45 J/g°C

Specific heat of Aluminium( Al ) = 0.897 J/g°C

Specific heat of Copper( Cu ) = 0.385 J/g°C

Specific heat of Tin( Sn ) = 0.227 J/g°C

Specific heat of Lead( Pb ) = 0.129 J/g°C

Power supplied is same for all cubes.

To Find:

The order of cubes that reach 80 °C fastest to slowest.

Solution:

The given question can be solved in this way.

We know that

Power Supplied P = ( m × C × dT ) / t

Where m = mass of the cubes = 100g

C = Specific heat of cubes

dT = Temperature difference = constant

t = Time Taken by cubes to reach 80 °C

Here, Power Supplied, Mass, and the Temperature difference are constant for all 5 cubes.

So, Time taken is directly proportional to the Specific heat of Substance

⇒ t ∝ C

Hence the metals with lower Specific heat will take less time and vice versa.

Given Specific heats

Specific heat of Iron( Fe ) = 0.45 J/g°C

Specific heat of Aluminium( Al ) = 0.897 J/g°C

Specific heat of Copper( Cu ) = 0.385 J/g°C

Specific heat of Tin( Sn ) = 0.227 J/g°C

Specific heat of Lead( Pb ) = 0.129 J/g°C

Therefore the order of increasing time taken is

1. Pb ( Fastest )

2. Sn

3. Cu

4. Fe

5. Al ( Slowest )

Therefore the increasing order of time taken is given by Pb < Sn < Cu < Fe < Al.

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