Question

A chemist was preparing solution that should have included 35 milligrams of a chemical. if she actually used 36.4 milligrams. what was her percentage error (to the nearest 0.01%)?

Answer 1

QUESTION --- A chemist was preparing solution that should have included 35 milligrams of a chemical. if she actually used 36.4 milligrams. what was her percentage error (to the nearest 0.01%)?

ANSWER
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Original value to be taken = 35 mg

Added value / New value = 36.4 mg

Error in addition = New value - Original value

Error = 36.4 - 35

Error = 1.4 mg
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Error % = Error / Original value × 100

Error % = 1.4 / 35 × 100

Error % = 14 / 350 × 100

Error % = 1 / 25 × 100

Error % = 4 %

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ANSWER = 4%
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HOPE IT HELPS :):):):):)