Question

A chess board contains 64 equal squares and the area of each square is 4cm2 . A border round the board is 2cm wide. Find the length of side of the chess board. (please answer quick)

Answer 1

Step-by-step explanation:

Let the length of the side of the chess board be x cm. Then,

Area of 64 squares = (x−4)^2

(x-4) ^2=64x4

x^2-8x+16=256

x^2-8x-240=0

x^2-20x+12x-240=0

x(x-20)+12(x-20) =0

(x+12)(x-20)

x=-12,x=20

Answer 2

Answer:let the length of side of a chessboard be×cm. Length can't be negative , so× =24 hence the length of the side of the chessboard =24 cm

Step-by-step explanation: let the length of the side chessboard be x cm.

Then area of 64 squares =(x-4)2 squares .

(x-4)2 squares =64×(6.25)

x square -8x +16=400

x square-8x -384=0

- 24x+16x - 384 =0

(X-24) (x+16) =0

X=24 cm.