A chess board is given .2 squares are choosen randomly.find the probability so that no common sides of square matches.
Answers
Answered by
0
We may count the couples of adjacent squares in the following way: for any square, we may consider how many adjacent squares there are, sum everything, divide by two:
4⋅2+24⋅3+36⋅42=112.
The couples of squares are (642)=2016, hence the wanted probability is
1122016=118.
pls-mark-as-brainliest.......
Similar questions
Hindi,
7 months ago
World Languages,
7 months ago
Math,
7 months ago
English,
1 year ago
English,
1 year ago