Question

A chess bored of the side is 63 cm and world map of length 112 cm and the breadth 65 cm find how much tape required to stich them both on the wall and which one get more tape ? If I want to stick these in 2 class rooins total how muck tape required for me ?

Answer 1

Answer:

Given side of square = 15 cm

then area of square=(side)

2

area of square =(15)

2

=225cm

2

area length of rectangle = 11 cm

breadth of rectangle = 8 cm

Then area of rectangle =l×b=11×8−88cm

2

∴ area of square > area of rectangle

&

diff in area =225−88=137cm

2