A chical box has each edge 10 cm and another cuboidal box is 123 cm long. 10 cm
wide and 8 cm high
Which box has the greater lateral surface area and by how much
Which box has the smaller total surface area and by how much
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1 . At first LSA of cube =4a²
=4× 10 ²
=400 cm²
Now LSA of cuboid= 2(l+b)h
=2(2.5+10)8
=2×22.5×8
=45×8
=360 cm²
There fore cube has a larger surface area.
2. Now the TSA of cube = 6a²
=6×10²
=600 cm²
Now the TSA of cuboid is
=2(lb+bh+hl)
=2(12.5×10+10×8+8×12.5)
=2(125+80+100)
=2×305
=610cm²
Therefore here cube has the smaller TSA.
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