Math, asked by 4453271, 23 hours ago

A child builds with blocks, placing 35blocks in the first row, 31 blocks in the
second row, 27 blocks in the third row, and so on. Continuing this pattern,
can she end with a row containing exactly 1 block? If not, how many blocks
will the last row contain? How many rows can she build this way?

Answers

Answered by ssaattyyaam100
1

Answer:

Not, she cannot end with a row containing exactly 1 block. Last row will contain 3 blocks. She can build total 9 blocks.

Step-by-step explanation:

  • 35 - 4 = 31
  • 31 - 4 = 27
  • 27 - 4 = 23
  • 23 - 4 = 19
  • 19 - 4 = 15
  • 15 - 4 = 11
  • 11 - 4 = 7
  • 7 - 4 = 3

Not, she cannot end with a row containing exactly 1 block because a row should contain

at least 4 blocks but last row is containing only 3 blocks.

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