Question

A child drop a ball from a window.
the ball stribes the ground in 3 sec-
What is the velocity when ball touches the
ground and distance covered in this
time interval ,​

Answer 1

Step-by-step explanation:

s = (U2)(T2) + (1/2)(9.81)(T2)^2

90m = (U2)(2.545) + (1/2)(9.81)(2.545)(2.545) metres

U2 = 22.88 m/s

The second ball must be launched with an initial downward velocity of 22.88 metres per second in order to reach the ground at the same time as the first ball.