a child drops a coin from the top of a building which is 50m high calculate the velocity of the coin when it falls through 20m distance and the velocity with which the coin strikes the ground (g=9.8m/s²)
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Answer:
Explanation:
case 1
initial velocity (u)=0m/s
final velocity (v)=?
height=20m
acceleration(a)=10ms^-2
using equation,
2as=v²-u²
2*10*20=v²-0²
400=v²
v=20m/s
CASE 2
initial velocity (u)=20m/s
final velocity (v)=?
height=50-20=30m
acceleration (a)=10ms^-2
again by using equation,
2as=v²-u²
2*10*30=v²-20²
600=v²-400
v²=1000
v=32.14m/s
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