Physics, asked by MrUntoward, 6 months ago

A child full set toy car through a distance of 10 meters on a smooth horizontal floor.
The string held in child's hand makes an angle of 60° with the horizontal surface. If the force applied by the child be 5 N.
Calculate the work done by the child in pulling the toy car​

Answers

Answered by ItzUltraParthStar
1

Answer:

Work = 60×10×5

=300

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Answered by Anonymous
125

Solution :-

Given :-

  • Angle between them (θ Theta) = 60°
  • Displacement (s) = 10 m
  • Force Applied = 5 N

To Find :-

  • Work Done (W)

Formula Used :-

 \underline{ \boxed{ \pink {\sf{Work \: Done = Force \times Displacement \times  \cos( \theta) }}}}

Substituting Values

 \sf\implies 5 \times 10 \times  \cos60 \degree

Now, for solving further Let's Understand it

 \boxed{ \green {\sf{ \: Cos \theta = Cosine \:  of angle  \: of  \: Elevation}}}

 \longrightarrow \sf Cos \:  60 \degree = \dfrac{1}{2}

Should Remember :-

 \bullet  \sf Cos \: 0 \degree = 1

\bullet  \sf Cos \: 36 \degree =  \dfrac{ \sqrt{3} }{2}

\bullet  \sf Cos \: 45 \degree =  \dfrac{1}{ \sqrt{3} }

\bullet  \sf Cos \: 60 \degree =  \dfrac{1}{2}

\bullet  \sf Cos \: 90 \degree = 0

\bullet  \sf Cos \: 180 \degree = 1 0

\bullet  \sf Cos \:  \theta \degree =  \dfrac{b}{h}

Therefore,

 \sf\implies 5 \times   \cancel{10 \times  \dfrac{1}{2} }

 \sf\implies 5 \times 5

\sf\implies2 5

Thus, Work Done is 25 Joule

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