A child had a certain number of peanuts. He gave two-thirds of these to the squirrels
and one-fourth of the remaining ones to the crows. He was then left with 12 peanuts.
How many did he have in the beginning?
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Answer:
x−(32x−41x)=12
let the no. of peanuts be x
on solving this equation u will get your answer.
hope you understood
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