Math, asked by akashkumarbarman, 6 months ago

A child had certain amount of chocolates . He ate 35%of the chocolates but still had 13 chocolates.what is the number of chocolates the child originally had?​

Answers

Answered by neha2663
7

Answer:

mei hoti vo chocolate bi nhi baj tha

I hate maths!!

sorry dude

Answered by parveenkumar410
2

Step-by-step explanation:

We are given that a child ate 35% of chocolates

So, chocolates left = 100%-35% = 65%

Let the total number of chocolates be x

We are also given that he left with 13 chocolates

So, A.T.Q

65\% \times x =1365%×x=13

\frac{65}{100} \times x =13

100

65

×x=13

x =13\times\frac{100}{65} x=13×

65

100

x =20x=20

Hence the number of chocolates the child originally had was 20

follow me Akash ji I will always help you

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