A child had certain amount of chocolates . He ate 35%of the chocolates but still had 13 chocolates.what is the number of chocolates the child originally had?
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7
Answer:
mei hoti vo chocolate bi nhi baj tha
I hate maths!!
sorry dude
Answered by
2
Step-by-step explanation:
We are given that a child ate 35% of chocolates
So, chocolates left = 100%-35% = 65%
Let the total number of chocolates be x
We are also given that he left with 13 chocolates
So, A.T.Q
65\% \times x =1365%×x=13
\frac{65}{100} \times x =13
100
65
×x=13
x =13\times\frac{100}{65} x=13×
65
100
x =20x=20
Hence the number of chocolates the child originally had was 20
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