Question

A child has a die whose faces are 6 show the letters given below
A B C A A B
The die is thrown once find the probability getting A and B

Answer 1

Total no of outcome=6(A,B,C,A,A,B)

chances of getting A and B =5(A,A,A,B, B)

probability=5/6.

Answer 2

Hey friend, your answer is-

Here n (s) = 6

Let P be the event that the letter

getting is A.

A = { A , A, A }

n (A) = 3

P (A) = n (A) / n(s)

P (A) = 3 / 6 = 1 /2

Let Q be the event that the getting letter is B.

B = { B , B }

n (B) = 2

P (B) = n (B) / n(s)

P (B) = 2 / 6 = 1 / 3

Hope it will help you.

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