A child has a die whose six faces show the letters A, B, C, D, E and F. The die is thrown
once. What is the probability of getting i) Vowel letter ii) Consonant letter on the top of
the die.
Answers
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Step-by-step explanation:
sample space (S) = { A,B,C,D,E,F}
n(s) = 6
(I) Event A : Sample space (A) = {a,e}
n(A) = 2
P(A)= n(A)/n(s)
= 2/6
= 1/3
(ii) Event B :. Sample space (B) = {B,C,D,F}
n(B) = 4
P(B)=n(B)/n(s)
=4/6
=2/3
BY ::: Rahul 10th STD
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