A child has a die whose six faces show the letters as show below .A, B, C, D, E, A,the die is throw once what is the probability of getting (i) A? (ii) D
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Answered by
0
Answer:
it's simple probability
Step-by-step explanation:
A 1/3 as there are two A from total 6 faces
D 1/6 for single D out of 6 faces
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Answered by
3
Step-by-step explanation:
Total no. of faces on the die =6
No. of faces having A on it =2
No. of faces having D on it =1
Therefore,
P(getting A)=
Total no. of faces
No. of faces having A
=
6
2
=
3
1
P(getting D)=
Total no. of faces
No. of faces having D
=
6
1
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