Question

a child has certain amount of chocolates he ate 35% of the chocolates but still has 13 chocolates what is the number of chocolates the child original held ​

Answer 1

Answer:20

Step-by-step explanation:

35% of X is eaten.

Remaining=100-35%

=65%

65% of X = 13

Therefore, X=(13*100)/65

=1300/65

=20

Answer 2

Question -:

A child has certain amount of chocolates. He ate 35% of the chocolates but still has 13 chocolates left. What is the number of chocolates the child had?

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Given -:

35% of the chocolates are eaten.

13 chocolates are left.

To find -:

The number of chocolates the child had before.

Explanation -:

Let the number of chocolates the child had be x.

35% of x is eaten.

Thus, the remaining % = 100% - 35% = 65%.

13 chocolates were left after eating.

Thus, 13 chocolates were remaining chocolates.

According to the question,

$65\% \: of \: x = 13$

$\frac{65}{100} \times x = 13$

Now, reduce the numbers. 65 and 100 both are divisible by 5. So reduce them and then multiply them by x.

$\frac{13x}{20} = 13$

$13x = 13 \times 20$

$13x = 260$

$x = \frac{260}{13}$

$x = 20 \: chocolates.$

Thus, the child had 20 chocolates.

Hope it helps! :)