Question

A child has three different kinds of chocolates costing Rs.2, Rs.5, Rs.10. He spends total Rs. 120 on the chocolates. what is the minimum possible number of chocolates he can buy, if there must be atleast one chocolate of each kind?

A) 22 B) 19 C) 17 D) 15

Answer 1

Answer:

In order to spend a total of not more than Rs. 120, he can buy Max. 53 & Min. 17 chocolates, with all above conditions.

Solution,

Since, he have three limits one is Rs. 120, second is one chocolate of each type is bought & the other is he can have minimal chocolates.

So, Re. 2, Re. 5 & Re. 10 will be used,

Here, the no. of chocolates inversely proportional to the rupees per chocolate, so,

For minimum no. of chocolates, we'll be using more of Re. 10 Chocolates,

Hence, (10)*10+(5)*2+(2)*5= 120,

Where as the bold ones are the no. of chocolates so,

10+2+5= 17,

Now, if asked max. no. of chocolates then,

(2)*50+(10)*1+(5)*2= 120,

Therefore, 50+1+2= 53

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