Math, asked by HrutikS09, 14 days ago

A child hears an echo from a cliff 4 seconds after the sound from a powerful
cracher is produced, How far away is the cliff from the child? Given that the speed
of sound is 340
m/s.​

Answers

Answered by Evilhalt
988

 \large \mathbb {GIVEN}

 \footnotesize \rm \bold{time \: taken \: by \: sound \: to \: travel \: from \: child \: to \: cliff}

\rm  \bold{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: t =  \frac{4}{2}  = 2s}

 \footnotesize \rm \bold{speed \: of \: sound \: in \: air : } \\  \rm \bold{v = 340  \:m/s }

 \footnotesize \rm \bold{diatance \: of \: cliff \: from \: child = speed(v) \times time(t)}

 \rm \bold{340 \times 2} \: m

 \rm \bold{ \rightarrow \: 680 \: m} \:  \:  \:  \rm{ans}

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