Question

A child is looking for his father. He went 90 metres in the East before turning to his right. He went 20 metres before turning to his right again to look for his father at his uncle’s place 30 metres from this point. His father was not there. From here he went 100 metres to the North before meeting his father in a street. How far did the son meet his father from the starting point?
a] 80 metres b] 100 metres c] 140 metres d] 260 metres

Answer 1

Answer:100 m

Step-by-step explanation:

you have to join the starting point with the end pint so that a triangle is formed.

then, use pythagora's theorem and u will get

(90-30)²+(100-20)²=60² + 80²=3600+6400=10000=100²

therefore,the answer is 100m

Answer 2

Answer:

Option b -  100m

Step-by-step explanation:

He went 90 metres in the East

Towards East - 90 m

Then he took Right means Went towards South

Towards South - 20 meter

Right From there means towards West

Towards West = 30 m

Then

Towards North = 100 m

Distance from origin

East - 90 m + West 30 m

= East 90 m - East 30 m

= East 60 m

North 100 m + South 20 m

= North 100 m - North 20 m

= North 80 m

So he is at a distance of North 80 m & East 60 m from origin

as North & East are perpendicular to each other

so by applying Pythagoras theorem

$Distance = \sqrt{60^{2} + 80^2} \\= \sqrt{3600 + 6400} \\= \sqrt{10000} \\= 100 \: m$

He is 100 m NE from Origin

Option b - 100m