Question

A child of mass 40 kg is sitting at a distance of 1m from another child of mass 50 kg. Calculate the gravitational force of attraction between them.?


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Answer 1

Answer:

Gravitational force of attraction between the two children is 1.33  × 10⁻⁷ N.

Explanation:

Given: Mass of first child = m₁ = 40 kg , mass of another child = m₂ = 50 kg and distance between the two children = 1 m

w.k.t., Gravitational force between two masses m₁ and m₂, placed at d distance apart is (G × m₁ × m₂)/d² where G is Universal gravitational constant and its value is 6.67 × 10⁻¹¹.

⇒ Force = (6.67 × 10⁻¹¹ × 40 × 50) / 1²

⇒ Force = 13340 × 10⁻¹¹

⇒ Force = 1.33  × 10⁻⁷ N

So, Gravitational force of attraction between the two children is 1.33  × 10⁻⁷ N.

Answer 2

Answer:

Gravitational force of attraction between the two children is 1.33  × 10⁻⁷ N.

Given: Mass of first child = m₁ = 40 kg ,

mass of another child = m₂

= 50 kg and distance between the two children

= 1 m

We Know That

Gravitational force between two masses m₁ and m₂, placed at d distance apart is (G × m₁ × m₂)/d² where G is Universal gravitational constant and its value is 6.67 × 10⁻¹¹.

⇒ Force = (6.67 × 10⁻¹¹ × 40 × 50) / 1²

⇒ Force = 13340 × 10⁻¹¹

⇒ Force = 1.33  × 10⁻⁷ N

So, Gravitational force of attraction between the two children is 1.33  × 10⁻⁷ N.