Question

a child of weight 20 kgf is sitting at a distance of 1.5 m from the fulcrum of a see saw . what is the moment of the force of weight of child? given that 1 kgf = 10 N​

Answer 1

Answer:

ELLO!!

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Explanation:

Here is your answer!!

This boy has a perpendicular distance of 2 m from the centre from the point of application of force 20 Kgf.

Hence moment of force is 20×2=40Kgf.

This must be balanced by horizontal by a man of having perpendicular distance from the centre on the side opposite to the boy is x with a weight of 40Kgf.

Hence moment of force is 40×x=40.

==>> Hence x=1m.

HOPE THIS MIGHT HELP YOU!!!