Question

A child pulls a toy car mass of 100g by applying a force at an angle 60degree.If toy car is displaced by 5meters in the horizontal direction then the work done is​

Answer 1

Explanation:

first change the mass in kg

W = mg

W = 0.1 × 9.8

W= 0.98 N

W = F

W = FScos60

W = 0.98 × 5 × 0.5

W = 2.45 J

Answer 2

Answer:

2.886 Joule

Explanation:

Let the child apply a pulling force F

on the toy car at an angle 60 degree to the horizontal.

Given, mass=m=100g=0.1 kg,

displacement=s =5m

As we know, there is no movement of the toy car in the vertical direction, we get

F × Sin 60 = mg = 0.1×10=1

F = 1/Sin 60= 2/sqrt 3

Work done = F×s×Cos 60

=(2/sqrt3)×5×(1/2)

=5/sqrt3

= 2.886 Joule