Question

a child puts one five rupee coin of her savings in the piggy bank on the first day she increases her saving by one five rupee coin daily. If the piggy bank and hold 190 coins of 5 rupees in all find the number of days she can contribute to put the five ruppe coins into it and find the total money she saved​

Answer 1

Answer:

190÷5=38

5--1 day

5+5-- 2 day

5+5+5---3 day

there fore in 38 days = 38×5=600

hope this helps u

have a nice day

Answer 2

Solution :-

The child puts in her piggy bank on first day = Rs. 5 coin

On second day she puts = 5 + 5 = Rs. 10

On third day she puts = 5 + 5 + 5 = Rs. 15

Her piggy bank can hold 190 5 rupee coin in all.

So, this is the case of an Arithmetic Progression.

5, 10, 15, ......................190

a = 5, d = 5 and n = 190

$\sf{S = \frac{n}{2} [2a + (n - 1)d] \: }$

⇒ $\frac{190}{2}$[2 ×5 + (190 - 1)5]

⇒ 95[10 + 189 × 5]

⇒ 95[10 + 945]

⇒ 95 × 955

= Rs. 90725

Her total saving is Rs. 90725