Question

A child rides her bike at a rate of 12.0 km/hr down the street. A squirrel suddenly runs in front of her so she applies the brakes and slows to 8.0 km/hr in 0.25 sec. What is the acceleration of the bike rider during this period?

Answer 1

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Answer 2

The acceleration of the bike rider during this period is $4.44\ m/s^2$ and he is retarding.

Explanation:

The initial speed of the child is 12 km/hr = 3.34 m/s

A squirrel suddenly runs in front of her so she applies the brakes and slows to 8.0 km/hr = 2.23 m/s

Time, t = 0.25 s

It is required to find the acceleration of the bike rider during this period. The acceleration is given by :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{2.23-3.34}{0.25}\\\\a=-4.44\ m/s^2$

So, the acceleration of the bike rider during this period is $4.44\ m/s^2$ and he is retarding.

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Acceleration

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