Question

a child runs around a rectangular building of length 10m and breadth 6m. the child runs around the building and come back to the same place of starting.the displacement of the child is​

Answer 1

Answer:

Displacement = 0

Explanation:

as per your question the child runs through rectangular field and returns back to the same point

distance = length of the path covered

distance = 2(10+6) = 2(16) = 32 m

displacement -= shortest distance between initial and final point

let initial point = x

ATQ

the boy returs to the same point

hence final point= x

displacement = x-x = 0

that answers our question

Happy to help !

Answer 2

Answer:

2 (10+16) = 2×26 =52 m

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