Question

A child’s game has 8 triangles of which 3 are blue and rest are red, and 10 squares of which 6 are blue and rest are red. One piece is lost at random. If all the outcomes are equally likely, then find the probability that it is, (i) a blue square (ii) a red triangle.

Answer 1

$\huge\pink{\fbox{\tt{࿐αɴѕωєя࿐}}}</p><p></p><p></p><p></p><p>$

According to the question, A child’s game has 8 triangles of which 3 are blue and rest are red, and 10 squares of which 6 are blue and rest are red.

Total number of pieces =8+10=18

No. of squares of blue colour = 6.

So, P(square of blue colour is lost)

= $\frac{6}{18}$ = $\frac{1}{3}$

No. of triangles of red colour =8−3=5

So, P(triangle of red colour is lost) = $\frac{5}{18}$