Question

A child thrown 2 fair dice. If the numbers showing are unequal, he adds them together to get his final score. On the other hand, if the numbers showings are equal, he throws 2 more dice and adds all 4 numbers showing to get his final score. The probability that his final score is 6 is :

Answer 1

Answer:

hello

Explanation:

hope it's help u thnku .

Answer 2

When two dices are thrown,The total outcomes when two dice are thrown=36

The number of outcomes of getting unequalnumber whose sum is 6={(1,5),(2,4),(4,2),(5,1)}

∴ The probability of getting unequal

numbers,P(UE)= 4/36

The number of outcomes of getting equal numbers,after throwing 2 more dice and summing all the outcomes to 6,

On first two dice as (1,1)→on second two dice as{(1,3),(2,2),(3,1)}

on first dice as (2,2)→on second two dice as{(1,1)}

∴The probability of getting equal numbers,

p (E) = (1/36 * 3/36) + (1/36 * 1/36) = 4/1296

The required probability = P(E) +

p(UE) = 4/36 + 4/1296 = 148/1296