Question

A child walks 8 kms towards south and then
moves 6 kms towards east from that point. How
far is he from his initial position?​

Answer 1

Answer:

14 km is the right answer for your question

Answer 2

Answer:

The child is 14 km far away from his initial position.

Explanation:

Total distance walked will be

$8 + 6 = 14 \: km$

Let the child be initially at A and let AC represent southern direction. Then,b= 8 km and a= 6 km. C will give displacement of the child as the displacement is the shortest distance between initial and final point

${c}^{2} = {a}^{2} + {b}^{2} \\ c = \sqrt{ {8}^{2} + {6}^{2} } = \sqrt{64 + 36} = \sqrt{100} = 10 \: km$

The child is 14 km far away from his initial position.