Question

a child weighing 25kg slides down a rope hanging from a branch of a tall tree. If the force of friction acting against him is 200N, the acceleration of the child is?

Answer 1

heyy user ur answer........

since child of weight is 250N  downward and and friction force 200N act on them.....
 so, net force=250-200=50N

so we known ,

F=ma,

a=f/m

a=50/25

a=2m/s

hope this will help u .........................@kundan

Answer 2

since child of weight is 250N downward and and friction force 200N act on them.....

so, net force=250-200=50N

so we known ,

F=ma,

a=f/m

a=50/25

a=2m/s^2

Mark as the brainliest...........