a child weight 160n on the surface of the earth calculate the weight of child at a height of 3.6×10 from the surface of earth radius of the earth is equal to 6.4×10
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weight of the child =160 N
=x * 9.8 (gravity)
thus, x=160/9.8
=16.33 kg
now,
R(radius of earth) =6.4 x 10
distance from the centre =3.6 x 10 + 6.4 x 10
=100
g=GM/R²
=6.673 x 10⁻¹¹ x 6 x 10²⁴ / 100²
=38(approx) x 10²⁴⁻¹⁵
=38 x 10⁹
weight of the child =16.33x38x10⁹
=x * 9.8 (gravity)
thus, x=160/9.8
=16.33 kg
now,
R(radius of earth) =6.4 x 10
distance from the centre =3.6 x 10 + 6.4 x 10
=100
g=GM/R²
=6.673 x 10⁻¹¹ x 6 x 10²⁴ / 100²
=38(approx) x 10²⁴⁻¹⁵
=38 x 10⁹
weight of the child =16.33x38x10⁹
Answered by
3
Answer:weight of the child =160 N
=x * 9.8 (gravity)
thus, x=160/9.8
=16.33 kg
now,
R(radius of earth) =6.4 x 10
distance from the centre =3.6 x 10 + 6.4 x 10
=100
g=GM/R²
=6.673 x 10⁻¹¹ x 6 x 10²⁴ / 100²
=38(approx) x 10²⁴⁻¹⁵
=38 x 10⁹
weight of the child =16.33x38x10⁹
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