Physics, asked by sam22, 1 year ago

a child weight 160n on the surface of the earth calculate the weight of child at a height of 3.6×10 from the surface of earth radius of the earth is equal to 6.4×10

Answers

Answered by manopollachi
16
weight of  the child =160 N
                              =x * 9.8 (gravity)
thus,  x=160/9.8
           =16.33 kg
now,
R(radius of earth) =6.4 x 10
distance from the centre =3.6 x 10 + 6.4 x 10
                                        =100
g=GM/R²
 =6.673 x 10⁻¹¹ x 6 x 10²⁴ / 100²
 =38(approx) x 10²⁴⁻¹⁵
 =38 x 10⁹
weight of the child =16.33x38x10⁹


Answered by Thegreat12345
3

Answer:weight of  the child =160 N

                              =x * 9.8 (gravity)

thus,  x=160/9.8

           =16.33 kg

now,

R(radius of earth) =6.4 x 10

distance from the centre =3.6 x 10 + 6.4 x 10

                                        =100

g=GM/R²

 =6.673 x 10⁻¹¹ x 6 x 10²⁴ / 100²

 =38(approx) x 10²⁴⁻¹⁵

 =38 x 10⁹

weight of the child =16.33x38x10⁹

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