a chips wrapper is 4.5cm long and 5.9 cm wide .it's area up-to significant figures will be?
Answers
Answered by
0
The chips wrapper has rectangular surface on either sides so
It's are =2×area of a rectangle
So area =2× l ×b =2×4.5×5.9=53.1
Now the term with lowest number of significant figures after decimal are both 4.5 and 5.9 ( 2 is not considered as it was not agiven measure) with one significant figure after decimal and the answer too have the same number of significant figures after decimal so
Area of the wrapper of the chips = 53.1 cm e2
If it helped Mark it as brainliest
It's are =2×area of a rectangle
So area =2× l ×b =2×4.5×5.9=53.1
Now the term with lowest number of significant figures after decimal are both 4.5 and 5.9 ( 2 is not considered as it was not agiven measure) with one significant figure after decimal and the answer too have the same number of significant figures after decimal so
Area of the wrapper of the chips = 53.1 cm e2
If it helped Mark it as brainliest
Similar questions