Question

A chocolate pastry costs Rs 26 and a fruit pastry costs Rs 18. Jessy buy both these pastries together for Rs 500. How many of each did she buy?

Answer 1

As the total no: of pastries bought isn't given we can only find the answer by trial and error method.
Lets assume the no: of chocolate pastry bought = x
and no: of fruit pastry bought = y


cost of 1 chocolate pastry = Rs 26
cost of x chocolate pastry = Rs 26x
similarly cost of fruit pastry = Rs 18 y
It is given that the total cost = Rs 500

therefore
Rs 26x + Rs 18 y = Rs 500

by trial and error method we can put various values for x and y and try to find the answer.
I have found the correct answer witha lot of effort, for my friend.

If we assume x= 4 and y = 22 , then
26 X 4 + 18 X 22 = Rs 500

104 + 396 = 500

∴ no: of chocolate pastries bought = 4
no: of fruit pastries bought = 22



please mark brainliest as i helped you first...

Answer 2

Let us assume that total no. of chocolate pastries be x and that of fruit pastries be y.

Therefore,

26x+18y= RS. 500

26×13+18×9=500

338+162=500

500=500

LHS=RHS

Therefore he bought 13 chocolate and 9 fruit pastries.