Question

A Choke coil takes a current of 2.5A when connected across 250V,50Hz mains and consume 400 watt.Find the power factor​

Answer 1

Answer:

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Explanation:

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Answer 2

The power factor is 0.64.

Given:

E = 250 V

v = 50 Hz

I = 2.5A

P = 400 watt

To Find:

Power Factor cos∅

Solution:

Power factor is the measure of how effectively the incoming power is used in an electrical system. Power factor is defined as the cosine of the angle between voltage and current.

Power P = EIcos∅

∴ cos∅ = $\frac{P}{EI}$

cos∅ = $\frac{400}{250*2.5}$

cos∅ = $\frac{400}{625}$

cos∅ = 0.64

Therefore, the power factor cos∅ is 0.64.

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