a chord 10 cm long is drawn in a circle whose radius is 5✓2
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Given, a chord AB of length 10 cm and radius = OA = OB = 5√2 cm. Construction: Draw OC perpendicular to AB. Now, AC = BC = 10/2 = 5 cm [The perpendicular drawn from the centre of a circle to a chord always bisect the chord.]
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