a chord a b of a circle with Centre o substance and angle of 120 degree at the centre is the radius of the circle is 30 cm find the area of a minor sector APB
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here is your answer. I hope it will help you.
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Answer:942 cm²
Step-by-step explanation:r=30cm
Φ=120
area of sector=Φ/360×Πr²
=120/360×3.14×30×30
=3.14×300
=942cm²
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