Question

A chord AB is produced on both sides to C and D such that AC = BD.CM and DN are two tangent on opposite side of CD prove that MN bisect AB?​

Answer 1

Answer:

O is the centre.

Given:-OM bisects equally AB..(1)

ON bisects equally CD..(2)

and AB bisects equally CD..(3)

⇒AB parallel ON and CD parallel OM

from equations (1),(2) and (3)

⇒ MP parallel ON and PO parallel OM (4) (5)

∴OMPN is a parallelogram.

(since opposite side are parallel.)

But angle ∠ONP=90° =(Given)

∠NPM=90°(Given)

∠NPM=∠NOM [opposite angles of parallelogram]

∴ all angles in the parallelogram are 90°

∴OMPN is a square or rectangle.

∴ length of perpendicular from centre to equal chords are equal.

⇒ON=OM

adjacent sides of rectangular OMPN are equal.

⇒ OMPN is a square

Answer 2

Step-by-step explanation:

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What is Cramer’s rule in the matrix?

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