Question

A chord AB of a circle of radius 10cm subtends a right angle at the centre.Find the area of the major and minor segments.

Answer 1

SOLUTION

Refer to attachment

hope it helps ✔️

Answer 2

Answer:

Step-by-step explanation:

radius r=10cm

angle =90

area of sector A=90/360pir^2

A=3.14x10x10/4

A=25x3.14

A=78.5sq.cm

Let the angle subtended and radius form an arc AOB,then

area of AOB=rxrsin90/2

AOB=10x10x1/2

ar. of AOB =50sq.cm

area of minor segment =78.5-50

=28.5aq.cm

Then area of circle =pir^2

=3.14x10x10

=314 Sq.cm

area of major segment =area of circle -area of minor segment

=314-28.5

=285.5sq.cm