Question

a chord AB of a circle of radius 14 cm makes an angle of 60° at the centre of the circle. find the area of the minor segment of the chord.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

l am only giving that how can you solve this question, firstly you have to draw a diagram IN which you have to draw a circle according to your question, make a chord IN the circle namely A and B. ,let the centre point be O join Ao and BO. and their radius will be also mention IN the figure that are 14cm, write the angle 60 degree, IN the figure according to your question, also take a point C on the circle b/w A and B,. now to find out the area of the shaded region you have to firstly find out the area of AOBC and area of AOB, .to find out the area of AOBC, draw a perpendicular from O to AB at D. you can show the AOD and OBD are similar by RHS similarity. now you can take Ad=BD and Angle AOD = ABOD =30degree. you can find out ADeasily by sin 30degree and by Pythagoras theoram you can find OD, now AB will be twice of AD and you can find out the area of triangle AOB (1/2bh) . now you will easily find the AOBC (angle as thighs)/360degree. pi r square) .now subtract the area of triangle AOB from the sector AOBC, you will get the area of the minor segment of the chord.