Question

A chord AB of a circle of radius 15 cm
makes an angle of 60° at the centre of the
circle. The area of the major segment is
(a) 68.61 cm
(b) 686.1 cm
(c) 6.861 cm (d) 686.1 m²
​

Answer 1

Answer:

D......686.1m.........

Answer 2

Answer:

Step-by-step explanation:

.Area of sector ABCD =πr^2¢/360°

=)22/7×15×15×60°/360°

=)117.85.

Area of ∆ABC.

=1/2r^2sin¢

=)1/2×15×15×√3/2

=)225√3/4

=)97.3125.

minor segment BDC=Area of sector ABDC-Area of triangle ABC.

=117.85-97.3125

=)20.53 ___1)

and again ,Area of circle =πr^2¢

=)22/7×15×15

=)707.14.cm^2.

.

so, major segment BDC

=)Area of circle - minor segment.

=)707.14-20.5

=)686.642 Ans

Mark me a brainlist please