A chord AB of a circle of radius 7cm subtends a right angle at the center. The area of minor segment.
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Answer:
Explanation:
In the mentioned circle,
O is the centre and AO =BO = Radius = 10 cm
AB is a chord which subtents 90
o
at centre O, i.e., ∠AOB=90
o
(i)
Area of minor segment APB (Shaded region) = Area of Sector AOB - Area of △AOB
=( 4 π×10×10 )−(0.5×10×10)
=78.5−50
=28.5cm
(ii)
Area of Major sector = Area of circle - Area of Sector AOB
= (π×10×10)−( 4 π×10×10 )
=314−78.5
=235.5cm
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