A chord AB of a circle with centre O is 10 cm. If the chord is 12 cm away f om centre, then what is the radius of the circle?
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radius of the circle is 13cm
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Answer:
AB=10cm
centre O
AD=1/2*AB(by perpendicular theorem)
AD=1/2*10
AD=5cm
OD=12cm
OA^2=OD^2+AD^2
OA=√12^2+5^2
OA=√144+25
OA=√169
OA=13
the radius of circle is 13cm
Step-by-step explanation:
the perpendicular bisector of a chord from centre divides the chord into two equal parts
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