A chord ab of a circle with centre o is 10 cm. If the chord is 12 cm away from centre, then what is the radius of the circle
Answers
Answer:
Step-by-step explanation:
GIVEN: A circle with centre O. Radius AO = 10cm, Chord AB = 12cm
TO FIND : The distance OM of the chord from O.
OM is perpendicular to the chord AB.
As, Perpendicular from the centre to a chord bisects the chord. So AM = AB/2 = 6cm
In right triangle AMO ,
AO² = AM² + OM² ( by Pythagoras law)
=> 10² = 6² + OM²
=> 100 = 36 + OM²
=> OM² = 100 - 36 = 64
=> OM = √64 = 8cm
Answer:
your answer
Step-by-step explanation:
GIVEN: A circle with centre O. Radius AO = 10cm, Chord AB = 12cm
TO FIND : The distance OM of the chord from O.
OM is perpendicular to the chord AB.
As, Perpendicular from the centre to a chord bisects the chord. So AM = AB/2 = 6cm
In right triangle AMO ,
AO² = AM² + OM² ( by Pythagoras law)
=> 10² = 6² + OM²
=> 100 = 36 + OM²
=> OM² = 100 - 36 = 64
=> OM = √64 = 8cm