A chord AB of a circle with centre O subtends an angle of 120° at the centre.If the radius of the circle is 30 cm, find the area of the minor sector APB root 3=1.7 =.14)
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area of sector = theta/ 360 × πr^2
thus, 120/360 × 3.14 × 900 ..........….......since 30^ 2=900
thus,1/3 × 314× 9
thus,area = 314 × 3 cm^2
=942
thus the area of the sector is 942 sq.cm
hope this helps you
and if yes then please mark this as brainliest........
thus, 120/360 × 3.14 × 900 ..........….......since 30^ 2=900
thus,1/3 × 314× 9
thus,area = 314 × 3 cm^2
=942
thus the area of the sector is 942 sq.cm
hope this helps you
and if yes then please mark this as brainliest........
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