a chord ab of radius 15 cm makes an angle of the 60° at the centre of circle. find the area of the major and minor segment
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area of minor segment = (60°/360° × π × 15×15) - (1/2 × sin60° × 15 × 15)
=1/6 × 22/7 ×225 - (1/2 ×√3/2 × 225)
=117.85-98.427
=20.423 ( Approx)
area of major segment =(180-60)/360×π×15×15 - (1/2×sin(180-60)×15×15)
=120/360×22/7×15×15 - (1/2×sin60×15×15)
=235.714-97.427
=138.287(Approx)
=1/6 × 22/7 ×225 - (1/2 ×√3/2 × 225)
=117.85-98.427
=20.423 ( Approx)
area of major segment =(180-60)/360×π×15×15 - (1/2×sin(180-60)×15×15)
=120/360×22/7×15×15 - (1/2×sin60×15×15)
=235.714-97.427
=138.287(Approx)
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