Question

A chord AB of the larger of the two concentric circle is tangent to the smaller circle at the point .show that c is the midpoint of chord AB

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given,

AB is a chord of a larger circle which is the tangent to the smaller circle.

To find,

We have to show that AC = BC

Solution,

We can simply prove that AC = BC by showing the congruency of the triangles.

In Δ ACO and ΔBCO

    AO = BO (radii of the same circle)

   ∠ACO=∠BCO (AB is tangent to the circle)

     OC = OC (common)

   Δ ACO≅ΔBCO(RHS)

       AC = BC(CPCT)

Hence, AC = BC by RHS congruency rule.