A chord and the diameter through one of its ends are drawn in a circle A chord of the same inclination is drawn on the other side of the diameter. prove that the chord are of the same length
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Answer:
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Step-by-step explanation:
THANKS FOR INCREASING MY POINTS........
Answered by
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Step-by-step explanation:
image is given below
AB is the diameter
AC and AD are the chords
Given that ∠OAC = ∠OAD
In triangle OAC,
∠OAC = ∠OCA
In triangle OAD,
∠OAD = ∠ODA
Consider the ΔOAC and ΔOAD
∠OAC = ∠OAD; ∠OCA = ∠ODA
∠AOC = ∠AOD; AO = AO
Triangles are equal.
Sides opposite to equal angles are also equal.
∴ AC = AD
i know its late
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