Question

a chord is 6 cm long is drawn in circle at distance of 5cm from centre of a circle whose diameter is 50 cm​

Answer 1

Answer:

Step-by-step explanation:

Also, let OC be the perpendicular drawn from O to AB

We know, that the perpendicular to a chord, from the centre of a circle, bisects the chord.  

∴AC=CB

=  

2

6

​

=3 cm

Now, △OCA is a right angled triangle.

Hence, applying the Pythagoras theorem, we get:

OA  

2

=OC  

2

+AC  

2

   

⇒OC  

2

=(5)  

2

−(3)  

2

           [OA=radius=5 cm and AC=3 cm]

⇒OC  

2

=16

∴ OC=4 cm

Hence, the distance of the chord from the centre of the circle is 4 cm.